How The Cowboys Finish 9-7

Use your ← → (arrows) to browse

Dec 29, 2013; Arlington, TX, USA; Dallas Cowboys tight end Jason Witten (82) runs after a reception against Philadelphia Eagles safety Patrick Chung (23) and linebacker Brandon Graham (55) at AT&T Stadium. The Eagle beat the Cowboys 24-22. Mandatory Credit: Matthew Emmons-USA TODAY Sports

On Sunday, I laid out how I foresee the NFC East shaping up.  Within this forecast, I predicted that the Dallas Cowboys will finish 9-7 and win the NFC East.  Am I out of my mind?  Probably.  That’s the thing about predictions, though.  Part of the fun is going out on a limb.  It’s not all puppy dogs and ice cream however.  This team, openly exposed flaws and all, can win nine games and nine games very well could be enough to win the division.

Nine wins would have been enough for the Cowboys to win the division in 2013 as well as 2012.  Nine wins was enough to win the division in 2011.  Besides, the truth of the matter is that the NFC East is not the dominating division it once was.  Factor in that the team who won the division last year did so based on the luxury of playing a fourth place schedule and the Cowboys’ main competition for first place has its own issues to worry about.  The Eagles have road games against Indianapolis, San Francisco, Green Bay and Arizona and home visits from Carolina and Seattle.  Those teams combined for a 66-29-1 record last season.  This doesn’t even factor in the six divisional games which are always more difficult than you expect.

Enough about the Eagles though, how do the Cowboys get to 9-7?  It’s not as impossible as you might think.  Let’s take a look at the second in chunks of four games at a time and breakdown how the East could be won.

Use your ← → (arrows) to browse
comments powered by Disqus