Cowboys Will Host Playoffs With These 3 Wins

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Oct 13, 2013; Arlington, TX, USA; Dallas Cowboys linebacker Sean Lee (50) jumps on the back of Washington Redskins running back Roy Helu Jr. at AT

WASHINGTON’S TOUGH SLEDDING

In my estimation, Washington currently has the best chance to rise up to the challenge and give Dallas the toughest run for their money.

However, the one thing going against them is their remaining schedule is absolutely, positively brutal.

Currently at 3-5, adding another loss from Dallas, that places them at assumingly 3-6.  With 7 other games left on the schedule, the Redskins would need to finish 6-1 (9-7) to best the 8-8 Cowboys.

Once again as with the Eagles, Dallas would own a series sweep and the head-to-head tiebreaker by defeating the Skins a second time.

So what 7 opponents would the Skins require snatching a minimum 6 wins from?

Road:  Minnesota,  Philly,  Atlanta,  NY Giants

Home:  San Francisco,  NY Giants,  Kansas City.

Two of those home opponents alone, the 49ers and Chiefs, have a 15-2 record.  Both of them will still be in vicious dogfights to win their divisions.

The likelihood of the 3-5 Redskins winning 6 of the 7 games (non-Cowboys) remaining is extremely far-fetched.  If they accomplished that feat then they’d deserve the crown above an 8-8 Dallas squad.

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