Cowboys Will Host Playoffs With These 3 Wins

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That’s right, I’m declaring this bold statement with 7 games left on the schedule.  The Dallas Cowboys can lock down the NFC East title and host a playoff game even with a 3-4 record (8-8 overall) over the final stretch.

Nov 3, 2013; Arlington, TX, USA; Dallas Cowboys receiver Dwayne Harris (17) celebrates his game winning touchdown in the fourth quarter against Minnesota Vikings cornerback Marcus Sherels (35) at AT

The key to this very achievable formula is beating the right 3 teams…

  • @ Washington
  • Philadelphia (season finale)
  • ONE single win among the other 5 contests

(@ New Orleans, @ NY Giants, Oakland, @ Chicago, or Green Bay)

There should be little doubt the Boys will topple at least one of the above 5 squads.  Oakland (Thanksgiving) and the Giants have a combined 5-11 record.

Pair that ONE victory with a triumph over the Redskins and Eagles, and keeping Dallas from the postseason is beyond far-fetched.

8-8 AGAIN YOU SAY?

I certainly don’t want Dallas to finish at 8-8, nor do I predict it.  I’m leaning with 9-7 being the final record.  A strong 9-7 as a few breaks early on and they would have picked up a few more early season wins.

Even closing the regular season with a 3-4 losing record, Dallas can all but lock down the division crown by gathering 3 specific victories against highly beatable opponents.

The 8-8 achieved with these specific wins is the best possible 8 loss advantage they could gain when compared to the other division opponents.

It provides a sweep over the NFC East contenders (Eagles, Skins), and at worst a split with the lowly Giants.  The special combination would give Dallas a minimum 5-1 division record.  No other NFC East team has less than 2 division losses NOW.

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